Booleans Comments
Comments
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=is an assignment, you probability want an equality check== -
I keep getting this error on everything for some reason??
Main.java:16: error: class, interface, or enum expected
public static void main(String[] args) {^Main.java:19: error: class, interface, or enum expected
int n = in.nextInt(doStuff(4,3));
^
Main.java:20: error: class, interface, or enum expected
for(int i=0; i -
@NK, you left out a
{afterelse. (This made the next}end the class of code.) -
Can someone give me the answer please... I cannot get it.
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@Nikki, see the first two comments...
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You can do this in one line of code:
return ((b%a)==0);
this is the same as
if( (b%a)==0){
return true;}
else{
return false;} -
boolean multiple = (a%b == 0);
return multiple;this code will work, I am 100% sure
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I didn't finish reading the whole lesson but what if
{
boolean haveMoneyLeft = yourMoney > yourDebts;
}What if I have a debt of 500gold and yourMoney is 500gold too
this makes:
{
boolean haveMoneyLeft = false;
}
right ? -
public static boolean doStuff(int a, int b){
boolean x = (a%b==0);
boolean y = (b%a==0);
if (a>b)
{
return x;
}
else
{
return y;
}
} -
boolean multiple = (a%b == 0);
return multiple;worked just fine, thank you!!!
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i used a longer way but it is still correct :)
public static boolean doStuff(int a, int b){
boolean check = false;
if (a%b == 0){
check = true;
}
return check;
} -
boolean multiple
if(a%b==0)
{
return true
}
else
{
return false;
} -
Help! 6/3 keeps coming out as false even though my code is:
public static boolean doStuff(int a, int b){
if (b%a==0){
return true;
}
else{
return false;
}
} -
it's a%b. You did the other way around.
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Bruh anybody got the answers..
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Nice this was an easy one. thanks again for the great site.
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import java.util.Scanner;
public class BooleanExm
{
public static void main(String[] args)
{
double a;
double b;
Scanner input = new Scanner(System.in);System.out.println ("Enter any number: "); a = input.nextDouble(); System.out.println ("Enter any number: "); b = input.nextDouble(); boolean output = a%b==0; System.out.println (output); }}
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import java.util.println;
public class Main(){
public static void main(String[] args){
int a = 4;
int b = 2;
if(a%b==0){
System.out.println("true");
}else{
System.out.println("false");
} -
import java.util.Scanner;
public class Main(){
public static void main(String[] args){
int a = 4;
int b = 2;
if((a%b)==0){
System.out.println("true");
}else{
System.out.println("false");
}
}
} -
Keep it simple, the answer is right there.....
boolean x;
if(a%b ==0){
x = true;
}
else{
x=false;
}
return x;
} -
In my solution, I used only =, not == , and I got a correct response. Can you tell me why that is? Thanks.
Rod
Nov 5, 3:53 AMThis error was returned. What is the problem with this syntax?
Main.java:6: error: unexpected type
return ((a%b) = 0);
^
required: variable
found: value
1 error