Correct Change I Comments
Comments

Sorry, I mistook nickels and pennies...

5, 4, 23 will result false !!!!!! it ca't be true 5*5 +4 = 24 ?????????????????

@Amboss, the challenge is to see if you can select the exact change from the coins you are given. So if you have 5 nickels, you can select 4 of them, add 4 pennies for a sum of 24 cents.

I've made the code, but when I run table below shows that all cases are correct EXCEPT that "Your Output" is incorrect, it's red.
I don't know why, I checked some made up cases manually on Eclipse. 
Кирилл, When given 7 nickels and 3 pennies, can you get 35 cents? Yes, you just select the nickels and ignore the pennies. Check your code to see what it returns.

Admin (?), I've make some changes, even few, but still, there is something wrong. Your example works, thanks for it!)
I'm just curious where I get lost. 
Кирилл. there's another example you're getting wrong. I think you should approach this problem a little differently. You can solve it with one ifelse statement.

You can solve it with one ifelse statement.
You're right. And only now it's shows "Correct". I have to say that with no mathematical help I won't do that. So, on my opinion this problem more related to mathematics rather then to programming. 
OMG :( this took me forever also my code is extensive.... looks like complying with DRY is going to take me looong time to master.

I solved !!
if (sum / 5 <= nickels && sum % 5 <= pennies){
return true;
}
else {
return false;
} 
At the end of my program I write << return boolean; >> but program say error:
variable bool might not have been initialized
return bool; 
I found my solution;
when I defined boolean bool I must give amount to it LIKE boolean bool = false; 
I solved it but some complicated:
boolean bool=false;
for (int i =0; i<=pennies; i=i+1){
if((sum  i)%5 == 0)
{ bool= true; break;}} return bool;

boolean statement worked for me
boolean bob = sum % 5 <=pennies;
return bob; 
boolean bob = sum%5<=pennies; return bob;

if(sum%5 > pennies) {return false;}
return nickels*5 + pennies >= sum; 
I archived many comments here with solutions. You can link to your solution (in your submissions) to share it, but you shouldn't paste the whole solution in here.

@mistermase nice. See also the featured answer

i'm confused i'm not familiar with nickel and pennies and cents . do they have relationships with each other ? like how many cents are there in pennies or in nickel ? :)

i'm really sorry :( we have different currency here in our country .... that's why i'm confused .

American Currency^{^} LOL

For those of you in different countries: Pennies are 1 cent, Nickles are 5 cents (each).

Added a note to main content on their value.


OK, but see the featured answers for a more concise answer.

I wrote my code in python. it's working if i run this in some other compiler but here it's not.
my code 
Boilerplate code for this challenge wasn't provided for Python, so you need to take in the input yourself from STDIN.

int nCount = sum / 5; if (nCount <= nickels) { return sum % 5 <= pennies; } else { return false; }

int a=sum/5;
int b=sum%5;
if(nickels>=a && pennies>=b){
return true;
}
return false; 
if ((sum%nickels) > pennies) return false; return true;
how the heck did this pass all the tests..

Thanks, that's actually an edge case that wasn't covered before. The last test case will now check that condition so that code no longer passes.

I did this way
if(nickels>=sum/5 && pennies>=sum%5)
{
return true;
}
else
{
return false;
} 
Here's some working boilerplate for Ruby:
n = gets.chomp.to_i
n.times do
input = gets.chomp.split(" ").map(&:to_i)
nickels = input[0]
pennies = input[1]
desired_sum = input[2]
print correct_change?(nickels, pennies, desired_sum), "\n"
end 
here goes my take!
if (sum % nickels <= pennies && ((nickels *5)+ pennies) >= sum){
return true;
}
else{
return false;
Hongwen
Nov 3, 9:36 PMFor input set 5 3 19, we can get 19 using 3 pennies and 4 nickels. So it should be true there.