Learn Python by Example Comments
Comments
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@Kavier, thanks, the challenge has been changed so you don't need an if-statement. (The boilerplate code can be ignored.)
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why doesn't this work?
if (a**b >= 2 * b**2 and a**b >= (a*b)**2) {
return True;
}
else return False; -
That's not the if-statement in python. Either peak ahead to control flow or solve the problem without an if-statement.
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The correct code is:
if (a**b >= 2*b**2) and (a**b >= (a*b)**2):
return True
else:
return False -
i think that the problem statement points to decision making , so IF construct is implied , but since it is not yet the time for control flow i used this code and it worked fine :
cond1 = a ** b >= 2 * b * b
cond2 = a ** b >= (a * b) ** 2
return(cond1 and cond2) -
What is the answer please of this challenge
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Answer added.
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I get the following compile error:
Traceback (most recent call last):
File "", line 1, in
File "/usr/lib/python2.7/py_compile.py", line 117, in compileraise py_exc
py_compile.PyCompileError: SyntaxError: ('invalid syntax', ('prog.py', 5, 12, '\t\tif i % 3 = 0:\n'))
What could the problem be?
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@Iavor, you probably mean
==
. -
Thank you, I somehow missed that.
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for n in ar: if n%3 == 0: print("no3",end=" ") else: print(n,end=" ")
It works on my computer interpreter, but at here got a syntax error,SyntaxError: invalid syntax.
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def do_stuff(ar):
#print array if you want:
str1 = ""
for n in ar:
if n%3 == 0:
str1 = str1 + "no3"+" "
else:
str1 = str1 + str(n) +" "
print(str1)
A correct but ugly answer. -
What
Kavier
Jul 3, 8:54 PMI believe only an if statement will solve this correctly since need to do one or the other, but it doesn't look like if statements are covered in this section :( Minor thing but I had to go find this out somewhere else due to it not being listed here.
Also, the for statement is used in the code but never actually exampled, same for the function use.