Challenge

The following Ruby code returns half of the maximum number in an array:

def max(ar)
  ar.max / 2
end

This code can now be passed an array and it will return the maximum number in it divided by 2:

 max([1, 3, 20]) #=> 10

The parameter in max is then modified as follows:

def max(*ar)
  ar.max / 2
end

Rewrite the above call to max so it works with the modified method. (Pass in the same numbers in the same order.)