Collatz Conjecture Comments
Comments
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For me it wasn't about stopping the loop but actually how to get the number print the first time(initial input) and the last time (1) without having the loop interfering.
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Whats wrong with my code? It keeps giving me the "Runtime error"
public static void doStuff(int num){ System.out.print(num + " "); while(num > 1){if(num % 2 == 0){ num = num/2; System.out.print(num + " "); }else{ num = num * 3 - 1; System.out.print(num + " "); } } } -
@Mikas Your else says "num = num * 3 - 1" it should be +1.
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I dont understand why would 3-1 cause runtime error?
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@Jig, you can get stuck in a loop, eg 5, 14, 7, 20, 10, 5 ...
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How did you know that it would get stuck in a loop. Thanks for the insight. Love what you guys are doing.
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while(num != 1){ System.out.print(num+" "); if(num%2==0) { num = num/2; } else { num = num*3+1; } } System.out.print("1"); -
@Learneroo should I create two loops?
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@Bernard, that's not necessary. You can create one
whileloop, with a condition inside it that determines what number to go to next. -
@learneroo that what I figured ...a for loop wouldn't work here.
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@learneroo that was a question...thanks
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Inside the loop, you can check if
numdivides by two or not, and then setnumto the appropriate value.
(See a solution if you're still stuck.) -
I got it right , but I'm not sure I understand how the if statements work in conjunction with the loops. Thanks
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the while loop will repeatedly run through the code (in its body) while a specified condition is true. anything can happen inside the loop body. in this case, an if-else
statement is used to set the value of
num. eventually,numreaches a value (1) that makes the while condition no longer true, so the loop ends. -
your correct output's are wrong.
for input=5 , the output should be 16 8 4 2 1 -
Sorry, due to a change yesterday it was mistakenly showing the number 5 for the count, it's been fixed.
zkvarz
Jan 17, 3:12 AMQuite simple, one problem was to stop the toop, eventually I've managed it.