Sum of the Squares

Comments

• 

  Jacknerik

  Dec 7, 4:44 PM

  Does ^ not mean "to the power of" in java? I kept trying i² but that didn't work, so I did i*i and that did.

• 

  Learneroo  

  Dec 8, 10:42 PM

  @jacknerik, ^ does not do "power" in Java. You can see the Java's main built-in math operations here: http://www.learneroo.com/modules/11/nodes/103. Your way was good, though there is also the

  cont...

  Java Math library, which hasn't been covered yet. (You can see it over here: http://docs.oracle.com/javase/6/docs/api/java/lang/Math.html )

• 

  Colm Forde  

  Nov 1, 7:13 PM

  I've entered this code
  for (int i = a; i <= b; i ++)
  {
  return (i * i);
  }

  when I run the program it tells me I am missing a return statement.

• 

  Bernard Mitchell  

  Jun 14, 6:02 PM

  for(int m=a; m<b; m=m+1){
          if(m>a&&m<b){
              return m*m+b*b+a*a
  

  someone explain why my code is wrong.

• 

  Learneroo  

  Jun 15, 4:29 PM

  Hint: Use a variable to keep track of the total sum and return that at the end.

• 

  Bernard Mitchell  

  Jun 17, 4:49 PM

  @Learneroo I tried creating an int that represents the total. For some reason my int that represents the numbers in the range only picks up the first number in the set. Can you explain what I'm doing wrong?

• 

  Learneroo  

  Jun 18, 8:20 PM

  @Bernard, create a variable sum before the loop, and then add the square of each number to sum. Then return sum after the loop.

• 

  Bernard Mitchell  

  Jun 19, 9:36 AM

  @learneroo when you say create a variable. Do you mean create an int variable? And if so I'm given only the first and last number how can I express the numbers in the range in an int? I was thinking a++.

• 

  Learneroo  

  Jun 19, 10:25 AM

  Yes, create an int variable. Then loop through the numbers from a to b. If you need more help see this code and modify it to add the squares instead of the numbers. See also Math with loops for more practice.

• 

  Bernard Mitchell  

  Jun 21, 2:24 PM

  @leaneroo when i plug in the provided code given in the above comment i get an error. I'm gonna work on it still just wanted to let you know. Thanks

• 

  Bernard Mitchell  

  Jun 28, 3:39 PM

  @learneroo , Finally got it but I don't quite understand still. In my equation does sum remain zero even as the loop goes on. I recall in past nodes that sum changes as the loop goes on. I may be wrong though. Thanks

• 

  Learneroo  

  Jun 28, 10:45 PM

  sum is declared outside the loop and set to 0, the loop modifies its value, so after the loop it has the value of whatever it was at the end of the loop. See also scope.

• 

  Bryan  

  Jan 8, 8:22 AM

  Why does this result in "Execution timed out. Please fix your code to execute faster."?

  static int doStuff(int a, int b){
      int sum = 0;
      for (int i=a;a<=b;i++) {
          int aPow = a*a;
          int bPow = b*b;
          sum += (aPow*bPow);
      }
      return sum;
  }
  

• 

  Learneroo  

  Jan 8, 11:24 AM

  Check if the loop will ever terminate. Will there be cases where a will never be less than b, so that the loop goes on forever?

• 

  Bryan  

  Jan 9, 3:17 AM

  Thanks. I just re-read my code after sleeping and can't believe I even wrote that.

• 

  avisuisse

  Sep 30, 10:31 PM

  sumsquare = function(a, b) {
  base = a²
  for (i in (a+1):b) {
  base = base + i²
  }
  print(base)
  }

• 

  omar

  Oct 17, 7:14 AM

  //by dart

  main() {
  var sum = SumoftheSquares(1, 3);
  print(sum);
  }

  SumoftheSquares(a, b) {
  int thesum = 0;
  for (int i = a; i <= b; i++) {
  thesum += i * i;
  }
  return thesum;
  }