No Sevens

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The next few challenges will involve loops, and this challenge can get you started.

The Kingdom of Zumbania recently banned the number 7. Please print all the numbers from 1 to 50 but skip all multiples of 7. Also, skip any number that has a 7 in it, such as 27.

Challenge

Print all the numbers as above, with each number on its own line.

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Comments

Кирилл Варивода
Jan 13, 5:50 AM

I can't even imagine using mod operator "to see if a number ends in 7". Web search didn't helped too.
Also, I do not see a reason to check if number divides by 7.
Кирилл Варивода
Jan 13, 10:49 AM

I do not see a reason to check if number divides by 7.

I got it.Then I put my code and it all works. It's just a mess of statements.
Now I see Explanation below, it's so easy now using only one if statement!
Davin
Jun 13, 7:39 AM

This is weird for me, it works until the number 14. How can it be the case?
Learneroo
Jun 13, 9:28 AM

@Davin, for specific feedback from admins on your code, consider signing up for membership or the bootcamp.
Viktor Ayadi
Jul 27, 9:20 AM

For finding out if the number ends with 7 you should check (number % 10) != 7
Bernard Mitchell
May 19, 11:04 AM

What is the correct phrasing for the print function. I keep getting an error when trying to test my code? Thanks
Bernard Mitchell
May 19, 10:16 PM

I keep getting errors in part of the code that I'm not altering. Can I please get some help on this? Thanks
Learneroo
May 19, 10:36 PM

This usually means you've changed the boilerplate code. In such a case, carefully copy your actual code, click "reset" and try again.
Bernard Mitchell
May 20, 11:16 AM

I keep getting an "cant find symbol error" when I try to print my int.. I'm going to have to cheat on this one. sigh
Bolke
Sep 24, 3:42 PM

I think I would like to get recognition for possibly having devised the longest, clunkiest and ugliest answer so far:

my code
Bolke
Sep 24, 3:45 PM

Ha, now I see the pitiful 3 lines of code given as the official answer...That won't cut it.
[insert smiley emoticon here.]
avisuisse
Oct 6, 8:45 PM

in R

for (i in 1:50) {

if (i == 7) {
next
}
else if (i %% 10 == 7) {
next
}
else print(i)

}

Dheeraj Parmar

Aug 4, 12:46 PM

#include

using namespace std;

int main()
{

for(int i=0;i<=50;i++)
{
    if( (i==7) || (i%7==0) || (i%10==7) )
    {
        continue;

    }
    else{
        cout<<i<<endl;
    }
}

}

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