Numbers to Words

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Given a number from 1 to 4 (inclusive), return a word representation of the number. For example, given 2, return two. If the number is greater than 4, return the phrase too large. If the number is less than 1, return the phrase too small.

Input/Output Format
Boilerplate code is provided for Java. For other languages, read in the numbers from the standard input in the following format.

The input starts with N, the number of cases.
N lines follow, which each contains 1 integer.

Print out the correct phrase for each case on its own line.

Click on "View Raw I/O" below to view sample input and output.

Challenge

'Convert' each Number to a Word, as described above.

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Comments

Victoria Holland
Jan 22, 7:29 AM

An interesting thing I discovered in this task is that you can't use return statements within a switch-block otherwise the compiler will say the break statements are unreachable. I had to assign

cont...
the word representations of the number to a String variable and then return that at the end of the method.
Learneroo
Jan 22, 9:28 AM

@Victoria, thanks. If you use a return statement, you should remove the break after it, since return exits the block of code. To help avoid errors, the Java compiler doesn't accept code it recognizes as unreachable (even if just a break statement).
Dino Šišić
Feb 21, 6:14 AM

You can make an String array and a new String after which you can do the following if for example num == 1 then assign the value of array[0] which is "one" in which case the new String equals "one". For too large and too small assign the "too large" or "too small" string from array if num < 1 and if num > 4 assign those strings from array to new String. Close all if and else if statements and return the new String.

cont...
Hope it helps
alan
Mar 29, 10:38 PM

Is there an easier way to do this? For the numbers 1-4 and other conditions, i made an individual if statement to save the string value to a variable. It seems kind of inefficient to write 6 if statements.
Learneroo
Mar 30, 11:48 AM

@alan, you can use a switch case instead. Click on "Featured Answers" above the Hint.

Bill

Apr 22, 1:03 AM

Need help
import java.util.Scanner;

public class Main {

public static String doStuff(int num){
    //your code here
    for(int i = 1; i < 5; i++){

cont...

        if(i == num){
            System.out.print(i);
        }
        else if(i > 4){
            return "too large";

        }
        else if(i < 1){
            return "too small";
        }
    }

}

public static void main(String[] args) {
    Scanner in = new Scanner(System.in);

    int n = in.nextInt();
    for(int i=0; i<n; i++){
        int a = in.nextInt();
        System.out.println( doStuff(a) );
    }
}

}

when i run this code, the compiler shows one error.
Main.java:21: error: missing return statement
}
^
1 error
how should do to solve this problem?

Budafai Gergely
Jul 20, 5:27 AM

My solution is:

String mes = "";
String[] onetofour = {"one", "two", "three", "four"};
for (int i =1; i<onetofour.length+1; i++) {
if (num== i) {
cont...
mes = onetofour[i-1]; } } if (num <1){ mes = "too small"; } if (num>4){ mes = "too large"; } return mes;

Macro

Aug 18, 10:52 PM

public static String doStuff(int num){
    //your code here
    String[] str = {"too small", "one", "two", "three", "four", "too large"};
    if(num < 1){
        return str[0];
    }
    else if(num > 4){
        return str[5];
    }else{
        return str[num];
    }
}

flowra
Feb 13, 5:55 PM

My solution and it is correct :
String result="";
String [] test = {"one","two","three","four"};
if (num 4) result= "too large";
cont...
else for (int i=0 ; i<test.length;i++) { if (num == (i+1)) result= test[i]; } return result;
Bernard Mitchell
May 14, 4:39 PM

This continuation of "if" and "else" problems doesn't explain how to convert numbers to text. Can you please explain?
Learneroo
May 14, 4:44 PM

You need to return a String.
Bernard Mitchell
May 15, 1:12 PM

Can I get an explanation on how to return a string? Like I said this wasn't covered in previous lessons.
Learneroo
May 15, 5:38 PM

Instead of return 5;, you do return "hello"; See String Class for more info.
Bernard Mitchell
May 20, 12:01 PM

Thank You
Bernard Mitchell
May 20, 1:47 PM

I keep getting errors in the code I didn't write and I haven't touched the boiler plate code.

import java.util.Scanner;

public class Main {
```
public static String doStuff(int num){
```
cont...
for(int c= 1; c<6; c=c+1){ if(num<=4 && num>0){ return "num"; } } }

}

This isn't the complete answer but what I've done so far
Bernard Mitchell
May 20, 3:49 PM

Never mind got it although I don't know if the way I did it is the most efficient. Thanks love this site!!!!

thales

Jul 15, 8:35 AM

what is wrong with this code:

    String number;
        switch(num){
        case 1:
            number= "one";
            break;
        case 2:
            number= "two";

cont...

            break;
        case 3:
           number = "thee";
            break;
        case 4:
            number= "four";
            break;
        default:
            if (num < 1){
            number= "too small";

            }
            else{
                numer="number too large";

            }
            break;
    }
return number;

thales
Jul 15, 8:53 AM

this code works in eclips?
thales
Jul 15, 9:06 AM

I think i have a very good queston ( at least i hope so).

Why isnt declaring enough en should i initialize the string. so
String message=""; works ( initializing)
String message; does not work, why not? for a string it does not mather right. i get it if it was an int but now??

Mari Garchagudashvili

Sep 9, 2:59 AM

What is wrong with this code?

textDef = ["Too small","One","Two","Tree","Four","Too large"]
def printText (num):
if num<1:
    print (textDef[0])
elif num>4:
    print (textDef[5])
else:
    print(textDef[num])

printText(2)

L

Nov 22, 3:51 AM

My solution

if(num < 1) return "too small";
if(num > 4) return "too large";

String[] words = {"one","two","three","four"};
return words[num-1];

Islam Elzohary
Dec 22, 4:55 AM

my code
https://www.learneroo.com/modules/20/nodes/147#&togetherjs=FcxFnlbpqR

Hanlise

May 14, 10:32 AM

def function1(a):
x=range (1, 5)
output=""
thisdict={
1:"One",
2:"Two",
3:"Three",
4:"Four"
}

cont...

if a in x:
    output += thisdict.get(a)
    return output
if a > 4:
    output= "too big"
    return output
if a < 1:
    output= "too small"
    return output

Using python

Roger
Aug 13, 7:51 PM

im not too comfortable with loops just yet but these are my 2 solutions on js:

/*function convert(a) {
let num = a
if (num < 1) {
return 'too small'

cont...
} else if (num == 1) {
return 'one'
} else if ( num == 2) {
return 'two'
} else if (num == 3) {
return 'three'
} else if (num == 4) {
return 'four'
} else if (num > 4) {
return 'too large'
} else {
return 'input a number'
}
};*/

const arry = ['too small', 'one', 'two', 'three', 'four', 'too high'];

function convert(a) {
let num = arry[a];

if(a < 1) {
return arry[0]
} else if (a > 4) {
return arry[5]
} else {
return num
}
}
Roger
Aug 15, 10:02 AM

const word = {
1: 'one',
2: 'two',
3: 'three',
};

function convert(i) {
let num = word[i]
if ( i < 1 || i > 3) {
return 'out of range'
} else {
return num
}
}